Question

How many different numbers of six digits can be formed with the number 3, 1, 7, 0, 9, 5 ?

• A. 500
• B. 400
• C. 300
• D. 600

Answer 1

The correct option is D 600

The number that can be formed, by taking digits together.
${=}^6{P}_6=6!$
But we have to neglect the number without with zero. Now the numbers in which zero with the $1^{st}$ place = 5!
Hencw, the required number = 6!-5!
= 720 - 120 = 600.