Question

How many six digit numbers can be formed using the digits $0,1,2,3,4,5$?

Answer 1

$\overline{5}\overline{6}\overline{6}\overline{6}\overline{6}\overline{6}$

$6ways-(0,1,2,3,4,5)$

$5ways-{(}^{\prime }{0}^{\prime }$cannot be placed as first digit $1,2,3,4,5)$

Total ways $=6^5\times 5=38,880$