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Question

How many different phenotypes and genotypes are obtained in Mendel’s F2 generation of dihybrid cross?


A

4 phenotypes and 9 genotypes

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B

4 phenotypes and 16 genotypes

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C

16 phenotypes and 8 genotypes

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D

2 phenotypes and 16 genotypes

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Solution

The correct option is A

4 phenotypes and 9 genotypes


Mendel considered two traits- seed colour and type for his dihybrid cross. He crossed two pure-bred varieties round yellow seeded plants (RRYY) with the (rryy) wrinkled green seeded plants, and self-fertilized the F1 hybrids (RrYy). The Punnett square here shows the different combinations of F2 progeny obtained.

The F2 progeny of Mendel’s dihybrid cross exhibit four different phenotypes: round yellow, round green, wrinkled yellow and wrinkled green.
And 9 different genotypes:

  • RRYY, RRYy, RrYY, RrYy - 4 genotypes of the round yellow phenotype
  • RRyy, Rryy- 2 genotypes of the round green phenotype
  • rrYY, rrYy- 2 genotypes of the wrinkled yellow phenotype
  • rryy- 1 genotype of the wrinkled green phenotype

Thus 4+2+2+1 = 9 genotypes
Of the four phenotypes, two are parental types and two are recombinants. Out of the 16 genotypes, there are 9 different types.


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