How many different words can be formed with the letters of the word ORANGE, with vowels occupying odd places?

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Solution

The correct option is C 36
The number of vowels in ORANGE = 3. No. of odd positions = 3.
3 vowels can be arranged in those 3 places in 3! Ways. similarly 3 remaining letters (Consonants) can be arranged in 3! Ways in the even positions. Hence, the total number of arrangements possible $= 3! \times 3! = 36$

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