Question

How many digits does the square root of a perfect square containing '$n$' digits has?

• A. $\frac{n+1}{2}$
• B. $\frac{n}{2}$
• C. Both A and B
• D. None of these

Answer 1

The correct option is C Both A and B

If 'n' is even then square root will contain $\frac{n}{2}$ digits

If 'n' is odd then square root will contain $\frac{n+1}{2}$ digits

For example: $\sqrt{625}=25$....square root of $3$ digit number has $\frac{(3+1)}{2}=2$ digits and $\sqrt{1225}=35$... square root of $4$ digit number has $\frac{\left(4\right)}{2}=2$ digits.