How many dry cells- each of e-m-f- 1-5 V and internal resistor 0-5- must be joined in series with a resistor of 20- to give a current of 0-6 A in the circuit-

The correct option is C 10 In series i=nEnr+R 0.6=n×1.5n×0.5+20 0.3n+12=1.5n 1.2n=12 n=121.2 n=10 ...

You visited us 50 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Physics

Resistors in parallel

How many dry ...

Question

How many dry cells, each of e.m.f. $1.5 V$ and internal resistor $0.5 Ω$ must be joined in series with a resistor of $20 Ω$ to give a current of $0.6 A$ in the circuit?

2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

8

No worries! We‘ve got your back. Try BYJU‘S free classes today!

10

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

12

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $10$
In series
$i = \frac{n E}{n r + R}$
$0.6 = \frac{n \times 1.5}{n \times 0.5 + 20}$
$0.3 n + 12 = 1.5 n$
$1.2 n = 12$
$n = \frac{12}{1.2}$
$n = 10$

Suggest Corrections

Similar questions

A 12 W resistor is connected in series with a cell of emf 1.5 V and negligible internal resistance (or terminal voltage 1.5 V). How must a 4 W resistor be introduced in the circuit, so that the current drawn from the cell is 0.5 A?

Q. Six secondary cells each of emf 3V and internal resistance 0.3Ω are joined in series with a 10Ω resistor. The potential drop across the external resistor is .

Q. The dry cell of e.m.f. 12 V, is connected in series to a

3 Ω

and a

6 Ω

resistor. Calculate the total power supplied by the dry cell.

Q. A battery of internal resistance,

3 Ω

is connected to

20 Ω

resistor and potential difference across the resistor is 10 V. If another resistor of

30 Ω

is connected in series with the first resistor and battery is again connected to the combination calculate the e.m.f. and terminal potential difference across the combination.

Q. The given figure shows a circuit diagram containing 12 cells, each of EMF 1.5 V and internal resistance

0.25 Ω

. Calculate the:

(a) total internal resistance.
(b) total EMF.
(c) reading shown by the ammeter.
(d) Current in

12 Ω

and

8 Ω

resistors.
[5 MARKS]

Join BYJU'S Learning Program

How many dry cells, each of e.m.f. 1.5 V and internal resistor 0.5Ω must be joined in series with a resistor of 20Ω to give a current of 0.6 A in the circuit?

The correct option is C 10In seriesi=nEnr+R0.6=n×1.5n×0.5+200.3n+12=1.5n1.2n=12n=121.2n=10

How many dry cells, each of e.m.f. $1.5 V$ and internal resistor $0.5 Ω$ must be joined in series with a resistor of $20 Ω$ to give a current of $0.6 A$ in the circuit?

The correct option is C $10$
In series
$i = \frac{n E}{n r + R}$
$0.6 = \frac{n \times 1.5}{n \times 0.5 + 20}$
$0.3 n + 12 = 1.5 n$
$1.2 n = 12$
$n = \frac{12}{1.2}$
$n = 10$