How many electrons are present in 18 mL of water?

Open in App

Solution

18 mL water = 18 g water = 1 mole water $= 6.02 \times 10^{23}$ molecules, each molecule consists 10 electrons (8 electrons per oxygen atom, 2 electrons for two hydrogen atoms). Total electrons $= 10 \times 6.02 \times 10^{23} = 6.02 \times 10^{24}$

Suggest Corrections

Similar questions

How many water molecules are present in one mL of water (d=1g/mL)?

18

1 k g L^{- 1})

Join BYJU'S Learning Program