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Question

How many electrons are present in 2×103 moles of 188O2 ?

A
1.2×1021
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B
9.6×1021
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C
1.2×1022
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D
1.9×1022
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Solution

The correct option is B 1.2×1022
188O2 total no of electrons =8+2
=10
1 mole of188O2 has 10×6.023×1023 electrons
2×103 moles of 188O2 has xelectrons
x=10×6.023×1023
x=1.2×1022

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