How many electrons can have $n = 4$ and $l = 2$ ?

6

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10

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18

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None of these

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Solution

The correct option is B $10$
$\begin{matrix} n = 4 and l = 2 is 4 d d-orbital maximum can have 10 electrons . \end{matrix}$

Suggest Corrections

Similar questions

n = 4, l = 1

m = + 1

C r^{+}

(i) n = 4, m_{s} = - \frac{1}{2}

(i i) n = 3, l = 0

(i i i) n = 2, l = 1

(i v) n = 2, l = 0

n = 4

l = 2

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