Question

How many electrons flow through a metallic wire if a current of $0.5A$ is passed for $2$ hours? (Given : $1F=96,500Cmo{l}^{-1})$

Answer 1

Charge passed:

$q=it=0.5\times 2\times 60\times 60=3600C$

Number of Faraday passed:

$F=\frac{3600}{96500}$

Number of electrons passed:

$N_e=\frac{3600}{96500}\times 6.022\times {10}^{23}=2.24\times {10}^{22}electrons$