Question

How many electrons in an atom with z = 104 can have $(n+l)=8$ ?

• A. 18
• B. 16
• C. 3
• D. 6

Answer 1

Answer: (B)

16

$Ru=$$1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^{10}4s^{2}4p^{6}4d^{10}5s^{2}5p^{6}4f^{14}5d^{10}6s^{2}6p^{6}5f^{14}6d^{2}7s^2$

For $6d$ and $5f$ orbital only$(n+l)=8$, which contains 16 electrons.