How many equivalent of $M g$ would have to react in order to liberate $4 N_{A}$ electrons? $(M g - 2 e^{-} \to M)$

1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

8

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $1$
$1$ mole of $M g$ liberate $2 e^{-}$ .
$4 e^{-}$ will be liberated by $2$ mol of $M g$ .
Now, equivalent of $M g = \frac{2}{2}$ mol
$= 1$ mol.
( $n -$ factor $= 2$ )

Suggest Corrections

Similar questions

M g^{2 +}

M (s) ⟶ M (g)

M (g) ⟶ M^{2 +} (g) + 2 e^{-}

M (g) ⟶ M^{+} (g) + e^{-}

M^{+} (g) ⟶ M^{2 +} (g) + e^{-}

M (g) ⟶ M^{2 +} (g) + 2 e^{-}

M

B_{2} O_{3} + M g \to M g O + B

B_{2} O_{3}

M g S O_{4}

H_{2}

H N O_{3}

Join BYJU'S Learning Program