How many genotypes are present among the 16 different combinations produced in the $F_{2}$ of a dihybrid cross?

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Solution

The correct option is B 9
${2^{n}}^{n}$ is the formula used for determining the number of gametes produced by organisms, where n represents the number of heterozygous genes present. In a dihybrid cross plant is heterozygous for two genes. So, $2^{n}$ = 4.

The dihybrid cross phenotypic ratio is 9:3:3:1 = 4 phenotypes, whereas the genotypic ratio is RRYY 1: RRYy 2: RRyy 1: RrYY 2: RrYy 4: Rryy 2: rrYY 1: rrYy 2: rryy 1. Thus, the number of genotypes is 9 for a dihybrid cross.

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How many genotypes are present among the 16 different combinations produced in the F2 of a dihybrid cross?

How many genotypes are present among the 16 different combinations produced in the $F_{2}$ of a dihybrid cross?