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Question

How many geometrical isomers are possible for the given compound?
CH3CH=CHCH=CHC2H5

A
Four
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B
Three
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C
Two
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D
Five
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Solution

The correct option is A Four

Since the number of double bonds in the given compound is 2 and the ends are different (i.e.CH3 and C2H5), therefore the total number of geometrical isomers are 22=4

Hence, the correct option is A

921027_928731_ans_6eec12dbb43e45d583545f0a654c5881.PNG

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