Question

The number of geometrical isomers in the following compound is:
$C{H}_3-CH=CH-CH=CH-C_2{H}_5$

• A. 4
• B. 3
• C. 2
• D. 5

Answer 1

The correct option is A 4

The given compound is a unsymmetrical compound. It has different terminal groups.
The formula used to determinne the number of geometrical isomers in compound having different terminal groups is, $2^n$, where n is the number of dounle bond present in the molecule.
In the given compound we have 2 double bond so n = 2
Therefore,
No. of geometrical isomers = $2^n$
= $2^2$
= 4.

Hence, unsymmetrical compound with 2 double bonds has 4 stereoisomers.