Question

The number of geometrical isomers of $C{H}_3-CH=CH-CH=CH-CH=CHCl$ are:

• A. 2
• B. 4
• C. 6
• D. 8

Answer 1

The correct option is D 8

The given compound is a unsymmetrical compound. It has different terminal groups ( methyl and chlorine).
The formula used to determinne the number of geometrical isomers in compound having different terminal groups is, $2^n$, where n is the number of dounle bond present in the molecule.
In the given compound we have 3 double bond so n = 3
Therefore,
No. of geometrical isomers = $2^n$
= $2^3$
= 8.

Hence, unsymmetrical compound with 3 double bonds has 8 stereoisomers.