The number of geometrical isomers of $C H_{3} - C H = C H - C H = C H - C H = C H C l$ are:

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Solution

The correct option is B 8
$C H_{3} - C H = C H - C H = C H - C H = C H C l$
In the given compound the number of double Bonds = $3$
So, the number of Geometrical isomers = $2^{3}$ $= 8$
The correct option is $D$

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