MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Diastereomers

How many geom...

Question

How many geometrical isomers are possible in a complex of type $[M a_{2} (A A)_{2}]$ , where a is unidentate and AA is bidentate symmetrical ligand?

A

0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

2

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D 2
In a complex of such type, the two A ligands can be arranged either adjacent to or opposite to each other to form cis and trans isomers respectively, making it a total of two possible isomers.

Option b is the correct answer.

Suggest Corrections

thumbs-up

0

Similar questions

Q. In case of the octahedral complex of the type

[M (A A) a_{2} b c]^{n \pm}

, possible number of geometrical isomer(s) is/are:
Here
AA is a symmetrical bidentate ligand
a,b,c are monodentate ligands

Q. Which of the following square planar complex does not show geometrical isomerism?

AA is symmetrical bidentate ligand
AB is unsymmetrical bidentate ligand
a and b are monodentate ligands

Q. Square planar complex of the type

M A X B L

(where A, B, X and L are unidentate ligands) shows following set of isomers.

Q. Why is geometrical isomerism not possible in tetrahedral complexes, having two different types of unidentate ligands coordinated with the central metal ion?

Q. Why is geometrical isomerism not possible in tetrahedral complexes having two different types of unidentate ligands coordinated with the central metal ion ?

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Standard XI Chemistry

Join BYJU'S Learning Program

CrossIcon