How many geometrical isomers are possible in $[A l (C_{2} O_{4})_{3}]^{3 -}$ ?

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Solution

The correct option is A 0
Oxalate is a bidentate and symmetrical ligand. Three oxalate gives CN=6 to Al and forms an octahedral shape.
It is of the type $[M (A A)_{3}]$ .
AA- bidentate symmetrical ligand

Since ligands are same, the structure of the complex will be same, such that no isomers are possible for this structure.
Option A is the correct answer

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