[AuCl4]−
Au+3=d8 configuration so it will not have any unpaired electron
[Co(H2O)6]3+
Co+3=d6d2sp3 hybridization so it doesnt have unpaired electron
Co(CO)4]−
d8dsp2 hybridization so it doesnt have unpaired electron.
As they all have no unpaired electron so they all are diamagnetic.