Question

How many co-ordination isomers are possible for the following complex? (Including given isomer)
$\left[Cr\right(N{H}_3{)}_6\left]\right[Fe\left(C_2{O}_4{)}_3\right]$

• A. $3$
• B. $4$
• C. $5$
• D. $6$

Answer 1

The correct option is B $4$


There are four possibility.
$\left[Cr\right(N{H}_3{)}_6\left]\right[Fe\left(C_2{O}_4{)}_3\right]$
$\left[Cr\right(N{H}_3{)}_4\left(C_2{O}_4\right)\left]\right[Fe\left(C_2{O}_4{)}_2\right(N{H}_3{)}_2]$
$\left[Cr\right(N{H}_3{)}_2\left(C_2{O}_4{)}_2\right]\left[Fe\right(C_2{O}_4{)}^{}\left(N{H}_3{)}_4\right]$
$\left[Cr\right(C_2{O}_4{)}_3\left]\right[Fe\left(N{H}_3{)}_6\right]$