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Ostwald Dilution Law

How many gram...

Question

How many gram ions of $S O_{4}^{- 2}$ are present in $1.25$ mole of $K_{2} S O_{4} \cdot A l_{2} (S O_{4})_{3} \cdot 24 H_{2} O$ .

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Solution

1 mole of $K_{2} S O_{4} . A l_{2} (S O_{4})_{3} .24 H_{2} O$ contains 4 gram ions of $S O_{4}^{2 -}$
1.25 mole of $K_{2} S O_{4} . A l_{2} (S O_{4})_{3} .24 H_{2} O$ contains = $4 \times 1.25$ gram ions = 5 gram ions of $S O_{4}^{2 -}$

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