How many gram ions of $S O_{4}^{2 -}$ are present in 1 gram molecule of $K_{2} S O_{4} . A l_{2} (S O_{4})_{3} . 24 H_{2} O$ ?

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Solution

The correct option is C 4
The total number of $S O_{4}^{2 -}$ ions present in 1 formula unit of $K_{2} S O_{4} . A l_{2} (S O_{4})_{3} . 24 H_{2} O = 4$

We know that ,one formula unit contains 1 mole of atoms, one gram ions equal to 1 mole

So, the total number of gram ions of $S O_{4}^{2 -}$ ions present in 1 gram molecule of $K_{2} S O_{4} . A l_{2} (S O_{4})_{3} . 24 H_{2} O = 4$

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S O_{4}^{2 -}

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K_{2} S O_{4} . A l_{2} (S O_{4})_{3} .24 H_{2} O

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