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Stoichiometric Calculations

How many gram...

Question

How many grams of $80$ % pure $N a_{2} S O_{4}$ can be produced from $130$ g of $90$ % pure $N a C l$ ?

177.5

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123.4

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145.8

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168.3

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Solution

The correct option is A $177.5$ g
2 moles of $N a C l$ will produce 1 mole of $N a_{2} S O_{4}$ .

The molar masses of $N a C l$ and $N a_{2} S O_{4}$ are 58.44 g/mol and 142 g/mol respectively.

130 g of 90% pure $N a C l$ corresponds to $\frac{130 \times 90}{100 \times 58.44} = 2$ moles.

They will produce 1 mole of $N a_{2} S O_{4}$ .

The grams of 80% pure $N a_{2} S O_{4}$ produced will be $\frac{100 \times 1 \times 142}{80} = 177.5 g$

Hence, option A is correct.

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