wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

How many grams of 80% pure Na2SO4 can be produced from 130 g of 90% pure NaCl?

A
177.5 g
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
123.4 g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
145.8 g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
168.3 g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 177.5 g
2 moles of NaCl will produce 1 mole of Na2SO4.

The molar masses of NaCl and Na2SO4 are 58.44 g/mol and 142 g/mol respectively.

130 g of 90% pure NaCl corresponds to 130×90100×58.44=2 moles.

They will produce 1 mole of Na2SO4.

The grams of 80% pure Na2SO4 produced will be 100×1×14280=177.5g

Hence, option A is correct.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Stoichiometric Calculations
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon