Question

How many grams of a dibasic acid (mol. weight 200 ) should be present in 100 ml of the aqueous solution to give the strength of 0.1 N?

• A. 10 g
• B. 2 g
• C. 1 g
• D. 20 g

Answer 1

Answer: (C)

1 g

$Normality=\frac{grameq.ofsolute}{volume\left(L\right)}$

Eq.wt of a dibasic acid =$\frac{M.wt}{2}=\frac{200}{2}=100$

$0.1=\frac{\frac{x}{100}}{0.1}$

$\therefore x=0.1\times 0.1\times 100=1gm$ of dibasic acid

Hence, option $C$ is correct.