How many grams of $C O_{2}$ will be produced upon combustion of 69 g of ethanol in an excess supply of oxygen?

110 g

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132 g

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176 g

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88 g

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Solution

The correct option is B 132 g
$2 C_{2} H_{5} O H + 7 O_{2} \to 4 C O_{2} + 6 H_{2} O$
Moles of ethanol given in the reaction = $\frac{69}{46} = 1.5$ moles
2 moles of ethanol give 4 moles of $C O_{2}$
1.5 moles of ethanol will give $\frac{4}{2} \times 1.5 = 3$ moles of $C O_{2}$
The mass of $C O_{2}$ = $3 \times 44 = 132$ g

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