How many grams of CO2 are produced by the complete reaction of 100 g CaCO3 with excess HCl ?
A
22 g
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B
44 g
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C
79 g
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D
110 g
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E
132 g
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Solution
The correct option is D44 g The molecular weights of CaCO3 and CO2 are 100 g/mol and 44 g/mol respectively. The balanced chemical equation is CaCO3+2HCl→CaCl2+H2O+CO2 Thus 1 mole (100 g) of CaCO3 produces 1 mole (44 g) of CO2. Hence 44 grams of CO2 are produced by the complete reaction of 100 g CaCO3 with excess HCl.