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Question

How many grams of K2Cr2O7 is required to oxidise 12.41 g of FeSO4 to Fe2(SO4)3 in an acidic medium? (K2Cr2O7=294;FeSO4=152)

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Solution

The reaction is:
6FeSO4+K2Cr2O7+7H2SO43Fe2(SO4)3+K2SO4+Cr2(SO4)3+7H2O

12.41 g of FeSO4 corresponds to 0.082 mole of FeSO4.

Mole of K2Cr2O7 required is 0.0826.

Hence, grams of potassium dichromate = 0.0826×294=4.018 gms

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