Question

How many grams of $K_{2}C{r}_2{O}_7$ are present in 1 L of its $\frac{N}{10}$ solution in acid medium?

Answer 1

Reaction of $K_{2}C{r}_2{O}_7$ in acidic medium:
$K_{2}C{r}_2{O}_7+H^{+}⟶C{r}^{3+}$
n-factor is 6.
Number of equivalents = $N\times V\left(inL\right)$
= $\frac{1}{10}\times 1=0.1$
So, $Weight=no.ofeqv.\times Eqv.wt.=4.9g$