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Question

How many grams of Na2S2O3 are needed to prepare five litres of an 8% solution (by mass) having density =1.075g/mL?

A
43.0g
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B
430g
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C
400g
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D
40g
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Solution

The correct option is B 430g
Na2S2O3 molar mass is 140 gram
8% solution by mass means 8 gram solute dissolved in 100 gram of solution
density = 1.075 g/ml means, 1075 grams soluton in one litre
Thus one gram solution contains 8/100 gram of solute
or 1075 gram solution contains (1075×8/100=86) gram solute
5 litre solution or (1075×5=5375) gram solutions contains 86×5=430 gram solute

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