How many grams of oxygen are required for complete combustion of 2 moles of benzene?

450g

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480g

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500g

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530g

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Solution

The correct option is B
480g

The balanced reaction for combustion of benzene is

$2 C_{6} H_{6} + 15 O_{2} \to$ $12 C O_{2} + 6 H_{2} O$

Therefore, 15 moles of oxygen gas is required for complete combustion of benzene.

We know that, $1 m o l e$ of $O_{2}$ = $32 g$

$∴$ $15 m o l e s$ of $O_{2}$ = $15 \times 32$ = $480 g$

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Similar questions

2 C_{6} H_{6} + 15 O_{2} \to 12 C O_{2} + 6 H_{2} O

39

C_{6} H_{6}

S T P

39 g m s

C = 12, H = 1, O = 16

2 C_{6} H_{6 (l)} + 15 O_{2 (g)} \to 12 C O_{2 (g)} + 6 H_{2} O_{(l)}

39 g

C = 12, O = 16

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