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Question

# Liquid benzene burns in oxygen according to 2C6H6(l)+15O2(g)→12CO2(g)+6H2O(l). How many litres of oxygen are required for complete combustion of 39g of liquid benzene ? (Atomic weight of C=12,O=16)

A
11.2
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B
22.4
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C
42
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D
84
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Solution

## The correct option is D 84The reaction is 2C6H6+15O2→12CO2+6H2O.The molecular weight of liquid benzene is 78 g per mole. Thus, 39 g of liquid benzene corresponds to 0.5 moles.2 moles of liquid benzene require 15 moles of oxygen for combustion. Thus, 0.5 moles of liquid benzene will require 0.5×152=3.75 moles of oxygen.1 mole of oxygen at STP will occupy 22.4 L. Hence, 3.75 moles of oxygen will occupy 3.75×22.4=84 L at STP.

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