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Question

Liquid benzene (C6H6) burns in oxygen according to 2C6H6(l)+15O2(g)12CO2(g)+6H2O(g)
How many litres of O2 at STP are needed to complete the combustion of 39 g of liquid benzene ?

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Solution

2C6H5+15O212CO2+6H2O

156 gm 480 gm

So for combustion of 39 g of C6H5,O2 required

=480×39156

=120 gm O2

So volume of =120 gm O2 at STP =22.4×12032

=84 ltr of oxygen

Therefore =84 ltr of oxygen is what is required to completely burn 39 g of liquid benzene.


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