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Question

Liquid benzene (C6H6) burns in oxygen according to the following equation:
2C6H6(l)+15O2(g)12CO2(g)+6H2O(g)
How many litres of oxygen at STP are required for the complete combustion of 39 g of liquid benzene?

A
74 L
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B
11.2 L
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C
22.4 L
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D
84 L
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Solution

The correct option is D 84 L
Moles of benzene=given mass molar mass=3978=0.5 mol

The given balanced chemical reaction is:
2C6H6(l)+15O2(g)12CO2(g)+6H2O(g)

As per the reaction, 2 moles of benzene reacts with 15 moles of O2.

Thus, 2 moles of benzene reacts with (15×22.4) L of O2.
Hence, 0.5 moles of benzene will react with (15×22.42)×0.5 L of O2
=84 L of O2

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