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Question

Liquid benzene (C6H6) burns in oxygen according to the following equation:
2C6H6(l)+15O2(g)12CO2(g)+6H2(g)
How many litres of oxygen at STP are required for the complete combustion of 117 g of liquid benzene?

A
272 L
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B
150 L
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C
354 L
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D
252 L
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Solution

The correct option is D 252 L
The given reaction is,
2C6H6(l)+15O2(g)12CO2(g)+6H2(g)

As per the reaction, 2 moles of benzene react with 15 moles of O2=15×22.4 L of O2
1.5 moles of benzene will react with = 15×22.42×1.5 L=252 L

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