Question

How many grams of oxygen gas contain the same number of molecules as 16 grams of sulphur dioxide gas?

Answer 1

We know that equal moles of all gases contain equal number of molecules
1 mole sulphur dioxide = $32+2\times 16=64g$
16g of sulphur dioxide = ----moles?
$=\frac{1}{64}\times 16=\frac{1}{4}mole$
$\frac{1}{4}$ mole of sulphur dioxide will have the same number of molecules as $\frac{1}{4}$ moles of oxygen
1 mole oxygen = 32 g
$\frac{1}{4}$ moles oxygen = ----?
$=\frac{1}{4}\times 32=8g$
$\therefore 8g$ of oxygen gas contain the same number of molecules as 16grams of sulphur dioxide gas