Question

How many grams of oxygen gas contains the same number of molecues in $16$ grams of sulphur dioxide gas? $(O=16uS=32u)$

Answer 1

Moles of $S{O}_2=\frac{16}{64}=0.25$

Given, Moles of $S{O}_2$=Moles of $O_2$

Hence, $0.25=\frac{m_{O_2}}{32}$

$\Rightarrow m_{O_2}=0.25\times 32=8g$