How many grams of oxygen $(O_{2})$ are required to completely react with $0.20 g$ of hydrogen $(H_{2})$ to yield water $(H_{2} O)$ ? (molar mass $H_{2} = 2 g/mol, O_{2} = 32 g/mol$ )

1.6

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0.8

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3.2

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Solution

The correct option is A 1.6
According to the reaction:
$2 H_{2} (g) + O_{2} (g) \to 2 H_{2} O (l)$
$4 g$ of hydrogen reacts with $32 g$ of oxygen.
So, $0.2 g$ of hydrogen reacts with $(\frac{32}{4} \times 0.2) = 1.6 g$ of oxygen

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