How many grams of sodium will have the same number of atoms as 6 grams of magnesium?
( $N a = 23, M g = 24$ )

5.75 g

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5 g

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5.50 g

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5.25 g

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Solution

The correct option is A $5.75 g$
Moles of $M g = \frac{6}{24} = \frac{1}{4} = 0.25 m o l e s$
$M o l e s o f M g = M o l e s o f N a$
$∴$ For $N a : 0.25 = \frac{x g}{23}$
$23 \times 0.25 = x g$
$= 5.75 g$

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In a compound of magnesium (Mg = 24) and nitrogen (N= 14 ), 18 g of magnesium combines with 7 g of nitrogen.
Deduce the simplest formula by answering the following questions:
(a) how many gram atoms of magnesium are equal to 18 g?
(b) how many grams atoms of nitrogen equal to 7 g of nitrogen?
(c) calculate simple ratio of gram atoms of magnesium to gram atoms of nitrogen and hence the simplest formula of the compound formed.

Which has more number of atoms, 100 grams of sodium or 100 grams of iron (given, atomic mass of Na = 23 u, Fe = 56 u)?

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How many grams of sodium will have the same number of atoms as 6 grams of magnesium? (Na=23,Mg=24)

The correct option is A 5.75 gMoles of Mg=624=14=0.25 molesMoles of Mg=Moles of Na∴ For Na: 0.25=x g2323×0.25=x g=5.75 g

How many grams of sodium will have the same number of atoms as 6 grams of magnesium?
( $N a = 23, M g = 24$ )

The correct option is A $5.75 g$
Moles of $M g = \frac{6}{24} = \frac{1}{4} = 0.25 m o l e s$
$M o l e s o f M g = M o l e s o f N a$
$∴$ For $N a : 0.25 = \frac{x g}{23}$
$23 \times 0.25 = x g$
$= 5.75 g$