    Question

# In a compound of magnesium (Mg = 24) and nitrogen (N= 14 ), 18 g of magnesium combines with 7 g of nitrogen. Deduce the simplest formula by answering the following questions: (a) how many gram atoms of magnesium are equal to 18 g? (b) how many grams atoms of nitrogen equal to 7 g of nitrogen? (c) calculate simple ratio of gram atoms of magnesium to gram atoms of nitrogen and hence the simplest formula of the compound formed.

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Solution

## a,b) Number of moles of magnesium atom = 1824=0.75 Number of moles of nitrogen = 714=0.5 Therefore, the number of grams atoms of magnesium in the compound = 0.75 The number of grams atoms of nitrogen in the compound = 0.5 C) Ratio of moles of magnesium and nitrogen atoms = 0.750.5=1.5:1=3:2 Therefore, the simple whole number ration of atoms of magnesium and nitrogen is 3:2 Since the ratio of magnesium and nitrogen atoms is 3:2, the empirical formula of the compound is Mg3N2.  Suggest Corrections  7      Similar questions
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