How many isomeric pentynes $(C_{5} H_{8})$ are possible :

3

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4

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5

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6

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Solution

The correct option is C $3$
$(i) C \equiv C - C - C - C - C$
$(i i) C - C \equiv C - C - C$
$(i i i) C \equiv C - C | C - C$
So, no of possible alkynes $= 3$

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