How many isomers of $C_{5} H_{11} O H$ will be primary alcohol?

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Solution

The correct option is B 4
$i) C H_{3} - C H_{2} - C H_{2} - C H_{2} - C H_{2} - O H$
$i i) C H_{3} + C - C H_{3} | C H_{2} | C H_{3} - O H$
$i i i) C H_{3} - C_{2} H_{5} | C H - C H_{2} - O H$
$i v) C H_{3} - C H_{3} | C H - C H_{2} - C H_{2} - O H$

Isomers of $C_{5} H_{11} O H$

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