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Bronsted Lowry Theory

How many lite...

Question

How many liters of $C l_{2}$ at STP will be liberated by the oxidation of $N a C l$ with 10 g $K M n O_{4}$ in acidic medium?
(Atomic weight: $M n = 55$ and $K = 39$ )

3.54

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7.08

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1.77

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None of these

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Solution

The correct option is C $3.54$
$10 N a C l + 8 H_{2} {S O}_{4} + 2 {K M n O}_{4} ⟶ {5 C l}_{2} + 2 {M n S O}_{4} + 5 {N a}_{2} {S O}_{4} + K_{2} {S O}_{4} + 8 H_{2} O$
$2 \times 158 = 316 g = 5 \times 22.4 L$ at $S T P$
$∴$ $10 g$ of ${K M n O}_{4} = \frac{5 \times 22.4 \times 10}{316} = 3.5 L$

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