How many litres of lime water should be added to a $40$ litres mixture containing lime water and water in the ratio of $1 : 3$ such that the resultant mixture has $50 %$ lime water in it ?

25

litres

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15

litres

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20

litres

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10

litres

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Solution

The correct option is C $20$ litres
Quantity of lime water in the mixture
$= \frac{1}{1 + 3} \times 40 = 10$ litres
Let the amount of lime water to be added be $x$ .
Then, $(40 + x) \times \frac{50}{100} = 10 + x$
$\Rightarrow 40 + x = 20 + 2 x$
$\Rightarrow x = 20$
Hence, $20$ litres of lime water should be added in the mixture.

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How many litres of lime water should be added to a 40 litres mixture containing lime water and water in the ratio of 1:3 such that the resultant mixture has 50% lime water in it ?

The correct option is C 20 litresQuantity of lime water in the mixture =11+3×40=10 litres Let the amount of lime water to be added be x. Then, (40+x)×50100=10+x ⇒40+x=20+2x ⇒x=20 Hence, 20 litres of lime water should be added in the mixture.

How many litres of lime water should be added to a $40$ litres mixture containing lime water and water in the ratio of $1 : 3$ such that the resultant mixture has $50 %$ lime water in it ?