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Question

# How many litres of O2 at STP are needed for the complete combustion of 80 g of liquid hexane (C6H14)? (Given:C6H14 +O2→CO2 + H2O)

A
55.6 L
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B
197.9 L
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C
94.6 L
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D
122.6 L
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Solution

## The correct option is B 197.9 L2C6H14 +19O2→12CO2 + 14H2O 2 moles of hexane reacts with 19 moles of O2 Molar mass of hexane = 12×6+14 g=86 g 86×2 g of hexane completely combusts in 19×22.4 L of oxygen at STP. 172 g of hexane completely combusts in 425.6 L of oxygen at STP. So, the amount of O2 required to completely combust 80 g of hexane =425.6172×80 L of oxygen at STP. = 197.9 litres of O2

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