How many litres of water must be added to 1 L of an aqueous solution of HCI with a pH of 1 to crearte an aqueous solution with pH of 2 ?

0.1 L

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0.9 L

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2.0 L

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9.0 L

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Solution

The correct option is D 9.0 L
$p H = 1 ∴ [H^{+}] = 10^{- 1} = 0.1 M p H = 2 ∴ [H^{+}] = 10^{- 2} = 0.01 M$
For dilution of HCI, $M_{1} V_{1} = M_{2} V_{2} w h e r e M_{1} = G i v e n c o n c e n t r a t i o n o f H C l M_{2} = C o n c e n t r a t i o n o f H C l w h i c h v o l u m e n e e d t o b e f o u n d V_{1} = G i v e n v o l u m e V_{2} = V o l u m e t o b e f o u n d P u t t i n g a l l t h e v a l u e s i n t h e a b o v e f o r m u l a, w e w i l l g e t 0.1 \times 1 = 0.01 \times V_{2} V_{2} = 10 L$
Volume of water to be added
$= 10 - 1 = 9 L$

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