How many moles in $44 g m$ of ${C O}_{2}$

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Solution

Molecular weight of $C O_{2} = (A t o m i c m a s s o f C) + 2 (A t o m i c m a s s o f O) = 12 + (2 \times 16) = 44 g / m o l$
$∴$ Moles of $C O_{2} = \frac{M a s s}{m o l e c u l a r m a s s} = \frac{44}{44} = 1 m o l e$

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