How many moles of $C O_{2}$ are present in 220 mg ?

5 moles

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0.005 mole

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5000 moles

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10 moles

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Solution

The correct option is B 0.005 mole
Weight of given sample of $C O_{2} = 220 m g = 220 \times 10^{- 3} g$

$no. of moles (n) = \frac{Weight of given sample}{molecular weight}$

$= \frac{220 \times 10^{- 3}}{44}$

$= 5 \times 10^{- 3} = 0.005 m o l e$

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