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Arrhenius Acid

How many mole...

Question

How many moles of ${A l}_{2} {(S O_{4})}_{3}$ would be in $50 g$ of the substances?

0.083 m o l

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0.952 m o l

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0.481 m o l

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0.140 m o l

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Solution

The correct option is C $0.140 m o l$
Moles $= \frac{M a s s}{M o l e c u l a r m a s s}$
Given, mass of ${A l}_{2} {(S O_{4})}_{3} = 50 g$ ,
Molecular mass of ${A l}_{2} {(S O_{4})}_{3} = 342 g$
$∴$ Moles of ${A l}_{2} {(S O_{4})}_{3} = \frac{50}{342} = 0.14 m o l$

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