How many moles of $B H_{3}$ are needed to react completely with 2 moles 1 pentene in hydroboration-oxidation reaction?

2 moles

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3 moles

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2/3 moles

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3/2 moles

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Solution

The correct option is B 2/3 moles
As $3$ moles of $B H_{3}$ reacts completely with $1$ mole of the alkene.
Now for 2 moles of an alkene, we require $\frac{2}{3}$ moles of $B H_{3}$ .

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